🔢 Algebra
|x| = k gives x = k OR x = −k
Absolute Value Equations — Distance from zero is always positive — so there are always two cases
1
Isolate the absolute value expression completely
Before splitting into two cases, get the absolute value bars completely alone on one side of the equation — nothing multiplied, added, or subtracted around them yet.
2
Split into two equations
Once isolated, |expression| = k splits into: expression = k, OR expression = −k.
3
Solve both equations separately
Solve each resulting equation using standard algebra steps — you'll typically get two different solutions.
4
Check both answers
Plug both solutions back into the original equation to confirm they work — occasionally one solution turns out to be extraneous.
1
Solve 3|x + 1| − 2 = 10. You cannot split into two cases yet — the absolute value isn't isolated; there's a 3 multiplying it and a −2 outside it.
2
Isolate first: add 2 to both sides (3|x+1| = 12), then divide by 3 (|x+1| = 4).
3
Now split: x + 1 = 4, OR x + 1 = −4. Solving each: x = 3, or x = −5.
4
Check both in the original equation — both satisfy 3|x+1| − 2 = 10, so both are valid solutions.

Exams test whether you isolate the absolute value expression completely before splitting into two cases — a step many students skip — and whether you check both resulting solutions.

The most common trap is splitting into two cases before the absolute value is fully isolated. If there's still a coefficient or constant outside the bars, isolate it first, then split.

1. What does |x| = k split into?
x = k OR x = −k.
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2. What must happen before you split an absolute value equation into two cases?
The absolute value expression must be completely isolated on one side of the equation.
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3. Solve 3|x+1| − 2 = 10.
x = 3 or x = −5.
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4. Why do you need to check both solutions at the end?
Because occasionally one of the two solutions turns out to be extraneous and doesn't actually satisfy the original equation.
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5. What does the mnemonic |x| = k represent conceptually?
That distance from zero is always positive, so a value k away from zero could be either +k or −k.
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